Given a non-empty array of integers, every element appears twice except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
Example 1:
Input: [2,2,1]
Output: 1 Example 2:
Input: [4,1,2,1,2]
Output: 4
class Solution:
def singleNumber(self, nums: List[int]) -> int:
record = set()
for n in nums:
if n in record:
record.remove(n)
else:
record.add(n)
return list(record)[0]